f(x)=ex+x−4
f′(x)=ex+1
xn+1=xn−f′(xn)f(xn) Initial solution x0=1
n012xn11.0757661.073729f(xn)−0.2817180.0080030.000006xn+11.0757661.0737291.073729
ε=∣∣xnxn+1−xn∣∣⋅100%
ε=∣∣11.075766−1∣∣⋅100%=7.5766%
ε=∣∣1.0757661.073729−1.075766∣∣⋅100%=0.1894%
ε=∣∣1.0737291.073729−1.073729∣∣⋅100%=0.000000%
x=1.073729
The root is 1.073729
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