2x5+x4−2x−1=x4(2x+1)−(2x+1)=
=(2x+1)(x4−1)=(2x+1)(x2−1)(x2+1)=
=(2x+1)(x+1)(x−1)(x2+1) x1=−1,x2=−21,x3=1
We know that there is a solution for the equation 2x5+x4−2x−1=0 in [0.5,1.5].
x=(2−x4+2x+1)1/5
xi+1=(2−xi4+2xi+1)1/5
i012345678xi0.50.9936701.0012390.9997511.0000500.9999901.0000021.0000001.000000
ε=∣∣nini+1−ni∣∣⋅100%
ε=∣∣0.50.993670−0.5∣∣⋅100%=98.734%
ε=∣∣0.9936701.001239−0.993670∣∣⋅100%=0.7617%
ε=∣∣1.0012390.999751−1.001239∣∣⋅100%=0.1486%
ε=∣∣0.9997511.000050−0.999751∣∣⋅100%=0.0299%
ε=∣∣1.0000500.999990−1.000050∣∣⋅100%=0.0060%
ε=∣∣0.9999900.999998−0.999990∣∣⋅100%=0.0016%
ε=∣∣0.9999981.000002−0.999998∣∣⋅100%=0.0012%
ε=∣∣1.0000021.000000−1.000002∣∣⋅100%=0.0002% If ε≤0.05%, then x=0.999998
The root is 1.00000
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