Question #196878

Compute all the minors and cofactors of

1 2 3

2 0 1

2 3 4


Expert's answer

A=[123201234]A=\begin{bmatrix} 1 & 2&3 \\ 2 & 0&1 \\ 2&3&4 \end{bmatrix}


Let MijM_{ij} stands for Minors and CijC_{ij} is cofactors

where i=ithi=i^{th} row and j=jthj=j^{th } column of the matrix


M11=∣0134∣=0−3=−3   ;  C11=(−1)1+1M11=−3 M12=∣2124∣=8−2=6  ;  C12=(−1)1+2M12=−6 M13=∣2023∣=6−0=6  ;  C13=(−1)1+3M13=6 M21=∣2334∣=8−9=−1  ;  C13=(−1)2+1M21=1 M22=∣1324∣=4−6=−2  ;  C22=(−1)2+2M22=−2 M23=∣1223∣=3−4=−1  ;  C23=(−1)2+3M23=1 M31=∣2301∣=2−0=2  ;  C31=(−1)3+1M31=2 M32=∣1321∣=1−6=−5  ;  C32=(−1)3+2M32=5 M33=∣1220∣=0−4=−4  ;  C33=(−1)3+3M33=−4M_{11}=\begin{vmatrix} 0 & 1 \\ 3 & 4 \end{vmatrix}=0-3=-3\ \ \ ;\ \ C_{11}=(-1)^{1+1}M_{11}=-3\\\ \\M_{12}=\begin{vmatrix} 2 & 1 \\ 2 & 4 \end{vmatrix}=8-2=6\ \ ;\ \ C_{12}=(-1)^{1+2}M_{12}=-6\\\ \\M_{13}=\begin{vmatrix} 2 & 0 \\ 2 & 3 \end{vmatrix}=6-0=6\ \ ;\ \ C_{13}= (-1)^{1+3}M_{13}=6\\\ \\M_{21}=\begin{vmatrix} 2 & 3 \\ 3 & 4 \end{vmatrix}=8-9=-1\ \ ;\ \ C_{13}=(-1)^{2+1}M_{21}=1\\\ \\M_{22}=\begin{vmatrix} 1 & 3 \\ 2 & 4 \end{vmatrix}=4-6=-2\ \ ;\ \ C_{22}=(-1)^{2+2}M_{22}=-2\\\ \\M_{23}=\begin{vmatrix} 1 & 2 \\ 2 & 3 \end{vmatrix}=3-4=-1\ \ ;\ \ C_{23}=(-1)^{2+3}M_{23}=1\\\ \\M_{31}=\begin{vmatrix} 2 & 3 \\ 0 & 1 \end{vmatrix}=2-0=2\ \ ;\ \ C_{31}=(-1)^{3+1}M_{31}=2 \\\ \\M_{32=}\begin{vmatrix} 1 & 3 \\ 2 & 1 \end{vmatrix}=1-6=-5\ \ ;\ \ C_{32}=(-1)^{3+2}M_{32}=5\\\ \\M_{33}=\begin{vmatrix} 1 & 2 \\ 2 & 0 \end{vmatrix}=0-4=-4\ \ ;\ \ C_{33}=(-1)^{3+3}M_{33}=-4




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