Let V= R^3
W=(x1,x2,x3)∣x1−x2=x3 . Show that W is a
subspace of V.
Further,find a basis for W and hence,find the dimension of W.
To show that W is a subspace of V we need to show the following:
let r=(r1,r2,r3) , q=(q1,q2,q3)∈W and α∈ field
⟹q1−q2=q3 and r1−r2=r3
- W is not empty
- for r,q ∈ W , r+q ∈ W
- αr∈W
if (0,0,0)∈ W then 0−0=0
therefore, W is not empty
r+q=(r1,r2,r3)+(q1,q2,q3)=(r1+q1),(r2+q2),(r3+q3)
since (r1+q1)−(r2+q2)=(r1−r2)+(q1−q2)=r3+q3
⟹r+q∈W
αr=α(r1,r2,r3)=r=(αr1,αr2,αr3)
then αr1−αr2=α(r1−r2)=αr3
⟹αr∈W
therefore W is a subspace of V
r=⎝⎛r1r2r3⎠⎞=⎝⎛r1r2r1−r2⎠⎞=r1⎝⎛101⎠⎞+r2⎝⎛00−1⎠⎞
∴,⎣⎡⎝⎛101⎠⎞⎝⎛00−1⎠⎞⎦⎤ is a Basis of W
The Dimension of W is 2
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