Find the matrix A that represents T relative to the usual basis of R2R^2R2 .we have
A= [352−7]\begin{bmatrix} 3 & 5 \\ 2 & -7 \end{bmatrix}[325−7]
So we look for the trace of A.
tra(A)= 3+(-7) = -4
det(A) = -31
The Characteristics polynomial is.
t2−tr(A)t+∣A∣ ⟹ t2−(−4)t+(−31)t2+4t−31t^2-tr(A)t+|A|\\ \implies\\ t^2-(-4)t+(-31)\\ t^2+4t-31\\t2−tr(A)t+∣A∣⟹t2−(−4)t+(−31)t2+4t−31
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