Answer to Question #143192 in Linear Algebra for Ojugbele Daniel

Question #143192

Let v be a vector space over F, define a spanning of v.


1
Expert's answer
2020-11-10T19:45:42-0500

First of all, if the original question is exactly how you have written it, the answer is trivial : the span of a vector space is the vector space itself. If it is not the case and you want a definition of a span of a vector, a set of vectors, or just a span of any subset XVX \subset V , here it is

We can define Span(X)Span(X) for XVX \subset V by two different manners:

  1. More abstract, but more universal and useful : Span(X)=Wvector subspace of V,XWWSpan(X) = \underset{W-\text{vector subspace of }V, X\subset W}{\cap} W . You take juste an intersection of all the linear (vector) subspaces of V containing X. For this definition to work you need to proof that an intersection of vector spaces is still a vector space, which is not that hard.
  2. More straightforward, you define Span(X)Span(X) by all possible finite (!!! it is important) linear combinations of vectors in X: Span(X)={i=1kλivi,viX,λiF}Span(X)=\{\sum_{i=1}^k \lambda_iv_i, v_i\in X, \lambda_i\in F\} . You can verify that it is indeed a vector space.

You can even proof that two definitions are equivalent and therefore you will have 2 different characterisations of Span(X)Span(X) : explicit formula approach (2) and the smallest space that contains X approach (1).

Remark : in the first definition i have considered only the case Span(X),XVSpan(X), X\subset V , as other cases (a vector or a set of vectors) are just particular cases of this.

Remark 2 : if Span(X)=VSpan(X)=V , we say that XX generates/spans/is a spanning set of VV .


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