a1=(1,1,1),a2=(0,1,1),a3=(0,1,−1)
We show that the vectors form the basis.
Consider a linear combination of vectors
αa1+βa2+γa3=0
and show that the numbers α,β,γ are equal 0.
αa1+βa2+γa3=0α(1,1,1)+β(0,1,1)+γ(0,1,−1)=(0,0,0)α=0α+β+γ=0α+β−γ=0α=β=γ=0
Then vectors a1=(1,1,1),a2=(0,1,1),a3=(0,1,−1) form the basis in R3
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