Suppose A is a 3x3 matrix such that det(A) =16.Find the value of det[(4(A^-1)^T]
Taking into account that "\\det(M^{-1})=\\frac{1}{\\det (M)}" and "\\det(M^T)=\\det (M)" for any matrix "M", we conclude that "\\det ((A^{-1})^T)=\\det (A^{-1})=\\frac{1}{\\det A}=\\frac{1}{16}."
Since "\\det(kM)=k^3\\det(M)" for any "3\\times 3" matrix "M",
"\\det (4(A^{-1})^T)=4^3\\det ((A^{-1})^T)=4^3\\frac{1}{16}=4."
Answer: "4."
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