Suppose C is a 3 x 3 matrix such that det (C) = 4 . Find det (C +C)
Let's consider C is a matrix given by
"\\begin{bmatrix}\n a & b&c \\\\\n d&e&f\\\\\ng&h&i\n\\end{bmatrix}"
them determinant of matrix C can be written as
"\\begin{vmatrix}\n a & b&c \\\\\n d&e&f\\\\\ng&h&i\n\\end{vmatrix}=4.........(1)"
Now,
"det(C+C)=\\begin{vmatrix}\n a & b&c \\\\\n d&e&f\\\\\ng&h&i\n\\end{vmatrix}+\\begin{vmatrix}\n a & b&c \\\\\n d&e&f\\\\\ng&h&i\n\\end{vmatrix}="
"=\\begin{vmatrix}\n 2a & 2b&2c \\\\\n 2 d&2e&2f\\\\\n2g&2h&2i\n\\end{vmatrix}=2\\times2\\times2\\times\\begin{vmatrix}\n a & b&c \\\\\n d&e&f\\\\\ng&h&i\n\\end{vmatrix}="
"=8\\times4\\space" from eq.(1)"="
"=32"
Answer:
"det(C+C)=32"
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