Let a11 x1 + a12 x2 + a13x3 = b1
a21 x1 + a22 x2 + a23 x3 = b2
a31 x1 + a32 x2 + a33 x3 = b3.
Show that if det (A) 6= 0 where det(A) is the determinant of the coefficient matrix;
then x2 = det(A2)
det(A) where det(A2) is the determinant obtained by replacing the second column of det(A)
by (b1; b2; b3)T :
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Expert's answer
2020-05-08T18:53:05-0400
Let us rewrite the linear system in a matrix form
⎝⎛a11a21a31a12a22a32a13a23a33⎠⎞⋅⎝⎛x1x2x3⎠⎞=⎝⎛b1b2b3⎠⎞ or A⋅⎝⎛x1x2x3⎠⎞=⎝⎛b1b2b3⎠⎞.
Here Aij are the elements of an adjugate matrix (https://en.wikipedia.org/wiki/Adjugate_matrix). Therefore, according to the rules of matrix multiplication we get
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