Question #110416
Express the following as a linear combination of

p1 = 3 + x + 2x2, p2 = 5 - x + 5x2, and p3 = 2 + 5x + 3x2.
1
Expert's answer
2020-04-21T14:00:46-0400

p1=2x2+x+3p_1=2x^2+x+3

p2=5x2x+5p_2=5x^2-x+5

p3=3x2+5x+2p_3=3x^2+5x+2

x2+x+1=a1(2x2+x+3)+b1(5x2x+5)+c1(2+5x+3x2)x^2+x+1=a_1(2x^2+x+3)+b_1(5x^2-x+5)+c_1(2+5x+3x^2)

x2(2a1+5b1+3c1)+x(a1b1+5c1)+(3a1+5b1+2c1)=x2+x+1x^2(2a_1+5b_1+3c_1)+x(a_1-b_1+5c_1)+(3a_1+5b_1+2c_1)=x^2+x+1

2a1+5b1+3c1=1;a1b1+5c1=1;3a1+5b1+2c1=12a_1+5b_1+3c_1=1;a_1-b_1+5c_1=1;3a_1+5b_1+2c_1=1

(3a1+5b1+2c1)(3a1+4b1+8c1)=1(3a_1+5b_1+2c_1)-(3a_1+4b_1+8c_1)=-1

b1=6c11b_1=6c_1-1 ---(1)

2(b15c1+1)+5b1+3c1=12(b_1-5c_1+1)+5b_1+3c_1=1

7b16c1+1=07b_1-6c_1+1=0 ---(2)

Solving (1) and (2) we get

c1=6/35c_1=6/35

Substituting this in equation(1) we get

b1=1/35;a1=6/35b_1=1/35;a_1=6/35

So,

x2+x+1=(6/35)(2x2+x+3)+(1/35)(5x2x+5)+(6/35)(2+5x+3x2)x^2+x+1=(6/35)(2x^2+x+3)+(1/35)(5x^2-x+5)+(6/35)(2+5x+3x^2)




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