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Solve :
x²y" -2xy' -4y=x²+2ln x
Solve :
dy/dx= 1/x+y+1
Solve (P+q) (px+qy) =1, using Charpit's method
Solve :
P² -2xyp + 4y²=0, where p=dy/dx
Solve :
x².d²y/dx² -x. dy/dx +y= ln x
Using the method of variation of parameters, solve the equation:
d²y/dx² +a²y = sec ax.
Solve:
x²y²(2ydx + xdy) - (5ydx + 7xdy) =0
If f(x, y) ={ 1 if x=0 or y=0 and 0 , otherwise } then lim f(x, y) does not exist for limit (x, y) approaches to (0, 0).
A uniform string of length l is struck in such a way that an initial velocity v0(constants) is imparted to the portion of the string between l/4 and 3l/4, while the string is in its equilibrium position. Find the subsequent displacement of the string as a function of x and t
Solve the problem of the vibrating string for the following boundary conditions
1. y(0,t)= 0
2. y(l,t)= 0
3. dy/dt(x,0)= v0 sin nπx/l
4. y(x,0)= y0 sin 2πx/l
#339914 on Dec 2023