Answer to Question #320548 in Differential Equations for Mudassir

Question #320548

Find the particular solution of the equation



e^2tdy/dx=4



Given that y=5, t=0

1
Expert's answer
2022-03-31T02:42:07-0400

e2tdy/dt=4e^{2t}dy/dt=4

dy/4=dt/e2tdy/4=dt/e^{2t}

y4=12e2t+C\frac{y}{4}=\frac{-1}{2e^{2t}}+C

y=5, t=0

C=5/4+1/2=7/4

y=2e2t+7y=\frac{-2}{e^{2t}}+7


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