Find the particular solution of the equation
e^2tdy/dx=4
Given that y=5, t=0
e2tdy/dt=4e^{2t}dy/dt=4e2tdy/dt=4
dy/4=dt/e2tdy/4=dt/e^{2t}dy/4=dt/e2t
y4=−12e2t+C\frac{y}{4}=\frac{-1}{2e^{2t}}+C4y=2e2t−1+C
y=5, t=0
C=5/4+1/2=7/4
y=−2e2t+7y=\frac{-2}{e^{2t}}+7y=e2t−2+7
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