Answer to Question #320548 in Differential Equations for Mudassir

Question

Find the particular solution of the equation

e^2tdy/dx=4

Given that y=5, t=0

Answer 1

$e^{2t}dy/dt=4$

$dy/4=dt/e^{2t}$

$\frac{y}{4}=\frac{-1}{2e^{2t}}+C$

y=5, t=0

C=5/4+1/2=7/4

$y=\frac{-2}{e^{2t}}+7$