Solution
Given equation may be rewritten in the form
dxdy=xyx2+y2=yx+xy
Let z=y/x => dxdy=dxdzx+z => dxdzx+z =z1+z => zdz = dx/x => ∫zdz=∫xdx => z2/2=ln|x|+C => C = z2/2 - ln|x| = y2/(2x2)-ln|x| => y(x)=2x2(C+ln∣x∣)
Answer
y(x)=2x2(C+ln∣x∣)
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