Find the differential equation of the family of curves x2+y2+2ax+2by+c=0, where a, b, c are parameters.
x2+y2+2ax+2by+c=02x+2yy′+2a+2by′=0y′(2b+2y)=−(2a+2x)y′=−(a+x)(b+y)\displaystyle x^2+y^2+2ax+2by+c=0\\ 2x + 2yy' + 2a + 2by' = 0\\ y'(2b + 2y) = -(2a + 2x)\\ y' = -\frac{(a + x)}{(b + y)}x2+y2+2ax+2by+c=02x+2yy′+2a+2by′=0y′(2b+2y)=−(2a+2x)y′=−(b+y)(a+x)
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