Ans:-
"f(x,y)=e^x siny+e^y cosx"
partial derivative with respect to x partial derivative with respect to y
"\\frac{\\partial f}{\\partial x} =e^x siny-e^ysinx" , "\\frac{\\partial f}{\\partial y}=e^xcosy+e^ycosx"
again partial derivative with respect to x again partial derivative with respect to y
"\\frac{\\partial^2 f}{\\partial x^2}=e^xsiny-e^ycosx" "-(i)" "\\frac{\\partial^2 f}{\\partial x^2}=-e^xsiny+e^ycosx" "-(ii)"
Add these two equations
"\\Rightarrow \\frac{\\partial^2 f}{\\partial x^2} +\\frac{\\partial^2 f}{\\partial y^2}=e^xsiny-e^ycosx+(-e^xsiny+e^ycosx)" "=0"
"\\Rightarrow \\frac{\\partial^2 f}{\\partial x^2} +\\frac{\\partial^2 f}{\\partial y^2}=0"
Hence Laplace's equation will be satisfied.
Comments
Leave a comment