d^3y/dx^3-3 d^2y/dx^3+ 4 dy/dx -2y=e^x+cosx
Solution.
"\\frac{d^3y}{dx^3}-3\\frac{d^2y}{dx^2}+4\\frac{dy}{dx}-2y=e^x+\\cos\u2061{x},"or
This is a linear differential equation of the third-order with constant coefficients. The general solution of this equation is found as the sum of the general solution "\\tilde{y}" of the corresponding homogeneous equation and some particular integral solution "y_*" of the inhomogeneous equation: "y=\\tilde{y}+y_*."
Сompose and solve the characteristic equation:
Therefore, "\\tilde{y}=C_1e^{\\lambda_1x}+C_2e^{ax}\\cos{bx}+C_3e^{ax}\\sin{bx},"
where "a" is a real part, and "b" is an imaginary part of complex numbers "\\lambda_2 \\text{ and } \\lambda_3." So,
The particular integral solution "y_*" is writte in the form:
Since the right-hand side contains a "\\cos{x}" , we look for a particular integral solution "y_1" in the form:
Using the method of undetermined coefficients we find that "A=\\frac{1}{10}" and "B=\\frac{3}{10}." So, "y_1=\\frac{1}{10}\\cos{x}+\\frac{3}{10}\\sin{x}."
Since the right-hand side also contains a "e^{x}" and 1 is characteristic number, we find a particular integral solution "y_2" in the form:
Using the method of undetermined coefficients we find that "C=1."
Therefore, "y_2=xe^{x}."
As follows, the particular integral solution of "\\frac{d^3y}{dx^3}-3\\frac{d^2y}{dx^2}+4\\frac{dy}{dx}-2y=e^x+\\cos\u2061{x}," is
and the general solution of the same equation is
Answer.
"y=C_1e^x+C_2e^x\\cos{x}+C_3e^x\\sin{x}+xe^x+\\frac{1}{10}\\cos{x}+\\frac{3}{10}\\sin{x}."
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