Answer to Question #129296 in Differential Equations for Hassan Rafique

Question #129296
Y=xdy/dx+1/2(dy/dx)^2
1
Expert's answer
2020-08-16T20:32:13-0400

As per the question,

y=xdydx\frac{dy}{dx}+d2y2dx2\frac{d^2y}{2dx^2}

Arranging the above equation as,

d2ydx2\frac{d^2y}{dx^2} +2xdydx\frac{dy}{dx} -2y=0 .....(1)(say)

let y=xt,

we take y=xt since It will fulfill the condition

since we have to reduce Second order differential equation into first order.

differentiate both sides with respect to x,

dydx\frac{dy}{dx} =t

Again differentiating above equation with respect to x,

d2ydx2\frac{d^2y}{dx^2} =dtdx\frac{dt}{dx}

Putting the above values in equation 1 we get,

dtdx\frac{dt}{dx} +2xt-2xt=0


dtdx\frac{dt}{dx} =0

so t=constant=k(say)

since t=yx\frac{y}{x}

soyxso \frac{y}{x} =k

y=kx

This is the required solution.



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