z=−76z6=−7z6=7eπiz6=7e(2πn+π)in=0,1,...5z=716e2πn+π6in=0,1,...5z=1.383e(πn3+π6)in=0,1,...5z=\sqrt[6]{-7}\\ z^6=-7\\ z^6=7e^{\pi i}\\ z^6=7e^{(2\pi n+\pi) i} \quad\quad n=0,1,...5\\ z=7^{\frac{1}{6}} e^{\frac{2\pi n+\pi}{6} i} \quad\quad n=0,1,...5\\ z=1.383e^{(\frac{\pi n}{3}+\frac{\pi}{6}) i} \quad\quad n=0,1,...5z=6−7z6=−7z6=7eπiz6=7e(2πn+π)in=0,1,...5z=761e62πn+πin=0,1,...5z=1.383e(3πn+6π)in=0,1,...5
six answers are,
z1=1.383eπ6iz2=1.383eπ2i=1.383iz3=1.383e5π6iz4=1.383e7π6iz5=1.383e3π2i=−1.383iz6=1.383e11π6iz_1=1.383e^{\frac{\pi}{6} i} \\ z_2=1.383e^{\frac{\pi}{2} i} =1.383i\\ z_3=1.383e^{\frac{5\pi}{6} i} \\ z_4=1.383e^{\frac{7\pi}{6} i} \\ z_5=1.383e^{\frac{3\pi}{2} i} =-1.383i\\ z_6=1.383e^{\frac{11\pi}{6} i}z1=1.383e6πiz2=1.383e2πi=1.383iz3=1.383e65πiz4=1.383e67πiz5=1.383e23πi=−1.383iz6=1.383e611πi
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Dear Shubham, please use the panel for submitting new questions.
Give another way for this answer using de moivre's theorem
Comments
Dear Shubham, please use the panel for submitting new questions.
Give another way for this answer using de moivre's theorem