"z_1*z_2 = r_ \n1\n (cos \u03b8_ \n1\n + j sin \u03b8_ \n1\n ) \\displaystyle\\times{r}_{{2}}{\\left( \\cos{\\ }\\theta_{{2}}+{j}\\ \\sin{\\ }\\theta_{{2}}\\right)}\n )\n= r_ \n1\n r_ \n2\n\u200b\t\n (cos[\u03b8_ \n1\n\u200b\t\n +\u03b8_ \n2\t\n ] \\displaystyle{\\left.+{j}\\ \\sin{{\\left[\\theta_{{1}}+\\theta_{{2}}\\right]}}\\right)}\n ])" is the final answer.
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