Question

Find the polar form of complex number (2+2isqrt(3))

Answer 1

$z=2+2\sqrt{3}i.$

$r=\sqrt{2^2+(2\sqrt{3})^2}=\sqrt{16}=4.$

$\phi=arctan(\frac{2\sqrt{3}}{2})=arctan(\sqrt{3})=\frac{\pi}{3}.$

Polar form: $z=4(cos(\frac{\pi}{3})+isin(\frac{\pi}{3}))$.