(a)Find the area of the region enclosed by the parabola π¦ = 2π₯ β π₯
2 and the π₯ axis.
(b) Find the value of π so that the line π¦ = ππ₯ divides the region in part (a) into two
regions of equal area.
Verify that the function π¦ = π1π (βπ+2π)π₯ + π2π (βπβ2π)π₯ is a solution to π¦ β²β² + 2ππ¦ β² + (π 2 + 4)π¦ = 0.
Evaluate the line integral
β«π(π₯, π¦, π§) Γ β π ,
where π(π₯, π¦, π§) = (π¦^2 , π₯, π§) and the curve πͺ is described by π = π¦ = π π₯ with π₯ β [0,1].Β
Question 4 Evaluate the line integral:
(i) of π(π₯) = 4π₯^3 along the line segment from (β2,1) to (1,2).
(ii) where the curve πΆ is parameterized through π₯(π‘) = cos π‘, π¦(π‘) = sin π‘ and π§ = π‘^2 with π‘ β [0,2π] of β«(ππ π + ππ π + ππ π) πΆ
(iii) β« π (π₯, π¦, π§) β β π« πΆ , where πΉ(π₯, π¦, π§) = (5π§^2 , 2π₯, π₯ + 2π¦) and the curve πΆ is given by π₯ = π‘, π¦ = π‘^2, and π§ = π‘^2 with π‘ β [0,1]
Question 3
Determine the length of the curve π₯ = π¦^2 /2 for 0 β€ π₯ β€ 1/2 . Assume π¦ positive.
Question 2
(i) Find the volume integral of the scalar field π(π₯, π¦, π§) = π₯^2 + π¦^2 + π§^2 over the region π specified by π₯ β [0,1], π¦ β [1,2], and π§ β [0,3].
(ii) Find the gradient of the scalar field π(π₯, π¦, π§) = π₯π¦π§ and evaluate it at the point (1,2,3). Hence, find the directional derivative of π at this point in the direction of the vector (1,1,0).
Question 1
(i) Construct the contour plot of the scalar field π: β2 β β such that π(π₯, π¦) = π₯ 2 β π¦.
(ii) Sketch the vector field π βΆ β2 β β2 defined as follows π(π₯, π¦) = (π₯ + π¦, βπ₯).Β
Convergence test forΒ "\\displaystyle\\sum_{n=1}^\\infty \\frac{sin(n)}{n}".
Given the domain(-2,-1,0,1,2), determine the range for each expression.Use a table of values
Use the definition of the derivative to differentiate V=(4)/(2)\pi r^(3).