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(a)Find the area of the region enclosed by the parabola 𝑦 = 2π‘₯ βˆ’ π‘₯

2 and the π‘₯ axis.

(b) Find the value of π‘š so that the line 𝑦 = π‘šπ‘₯ divides the region in part (a) into two

regions of equal area.


Verify that the function 𝑦 = 𝑐1𝑒 (βˆ’π‘˜+2𝑖)π‘₯ + 𝑐2𝑒 (βˆ’π‘˜βˆ’2𝑖)π‘₯ is a solution to 𝑦 β€²β€² + 2π‘˜π‘¦ β€² + (π‘˜ 2 + 4)𝑦 = 0.


Evaluate the line integral

βˆ«π’–(π‘₯, 𝑦, 𝑧) Γ— ⅆ𝒓 ,

where 𝒖(π‘₯, 𝑦, 𝑧) = (𝑦^2 , π‘₯, 𝑧) and the curve π‘ͺ is described by 𝒛 = 𝑦 = 𝑒 π‘₯ with π‘₯ ∈ [0,1].Β 


Question 4 Evaluate the line integral:

(i) of 𝑇(π‘₯) = 4π‘₯^3 along the line segment from (βˆ’2,1) to (1,2).

(ii) where the curve 𝐢 is parameterized through π‘₯(𝑑) = cos 𝑑, 𝑦(𝑑) = sin 𝑑 and 𝑧 = 𝑑^2 with 𝑑 ∈ [0,2πœ‹] of ∫(π’šπ’…π’™ + π’™π’…π’š + 𝒛𝒅𝒛) 𝐢

(iii) ∫ 𝐅(π‘₯, 𝑦, 𝑧) β‹… ⅆ𝐫 𝐢 , where 𝐹(π‘₯, 𝑦, 𝑧) = (5𝑧^2 , 2π‘₯, π‘₯ + 2𝑦) and the curve 𝐢 is given by π‘₯ = 𝑑, 𝑦 = 𝑑^2, and 𝑧 = 𝑑^2 with 𝑑 ∈ [0,1]


Question 3

Determine the length of the curve π‘₯ = 𝑦^2 /2 for 0 ≀ π‘₯ ≀ 1/2 . Assume 𝑦 positive.


Question 2

(i) Find the volume integral of the scalar field πœ™(π‘₯, 𝑦, 𝑧) = π‘₯^2 + 𝑦^2 + 𝑧^2 over the region 𝑉 specified by π‘₯ ∈ [0,1], 𝑦 ∈ [1,2], and 𝑧 ∈ [0,3].

(ii) Find the gradient of the scalar field 𝑓(π‘₯, 𝑦, 𝑧) = π‘₯𝑦𝑧 and evaluate it at the point (1,2,3). Hence, find the directional derivative of 𝑓 at this point in the direction of the vector (1,1,0).


Question 1

(i) Construct the contour plot of the scalar field 𝑇: ℝ2 β†’ ℝ such that 𝑇(π‘₯, 𝑦) = π‘₯ 2 βˆ’ 𝑦.

(ii) Sketch the vector field 𝑉 ∢ ℝ2 β†’ ℝ2 defined as follows 𝑉(π‘₯, 𝑦) = (π‘₯ + 𝑦, βˆ’π‘₯).Β 


Convergence test forΒ "\\displaystyle\\sum_{n=1}^\\infty \\frac{sin(n)}{n}".


Given the domain(-2,-1,0,1,2), determine the range for each expression.Use a table of values


Use the definition of the derivative to differentiate V=(4)/(2)\pi r^(3).


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