Question #264280

Use the definition of the derivative to differentiate V=(4)/(2)\pi r^(3).


1
Expert's answer
2021-11-17T15:42:20-0500

Rewriting the expression given


V=42πr3V=\frac{4}{2}\pi\>r^3


V=2πr3V=2\pi\>r^3


Derivative is defined as ΔyΔx\frac{\Delta\>y}{\Delta\>x}


In a graph of V against rr


Derivative will be defined as ΔVΔr\frac{\Delta\>V}{\Delta\>r}


Taking two general points on the graph


(r,2nr3)(r, 2nr^3) and (r+Δr,2π[r+Δr]3)(r+\Delta\>r,2\pi[r+\Delta\>r]^3)



ΔVΔr=2π[r+Δr]32πr3(r+Δr)r\frac{\Delta\>V}{\Delta\>r}=\frac{2\pi[r+\Delta\>r]^3-2\pi\>r^3}{(r+\Delta\>r)-r}



=2π[r3+3r2Δr+3r(Δr)2+(Δr)3r3]Δr=\frac{2\pi[r^3+3r^2\Delta\>r+3r(\Delta\>r)^2+(\Delta\>r)^3-r^3]}{\Delta\>r}



=2π[3r2+3rΔr+Δr2]=2\pi[3r^2+3r\Delta\>r+\Delta\>r^2]



As Δr0,\Delta\>r\to0,

Then ΔVΔr=6πr2\frac{\Delta\>V}{\Delta \>r}=6\pi\>r^2


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS