(a):
I=β«x2+1βxβdx
I=β«x2+1βxβdx
Put x2+1=t
β2xdx=dtβxdx=2dtβ
So, I=21ββ«tβ1βdt
I=21ββ«tβ1βdt
I=21ββ«tβ1/2dt=21β.1/2t1/2β+c=tβ+c=x2+1β+c
I=21ββ«tβ1/2dt=21β.1/2t1/2β+c=tβ+c=x2+1β+cI=21ββ«tβ1/2dt=21β.1/2t1/2β+c=tβ+c=x2+1β+c
(b):
The graph using matlab from (-5,5) is as follows:
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