SOLVE AND SHOW COMPLETE SOLUTION
1. if y= ax^3 + bx^2 and its point of inflection is at (2,8), what are the values of a and b?
2. graph the curve and find the point of inflection: y= (9x^2 - x^3 + 6)/ (6).
3. graph the curve and find the point of inflection: y= x^3 - 3x^2 + 6.
1.
"y'=3 ax^2 +2 bx"
"y''=6ax+2b"
"y''(2)=0=>6a(2)+2b=0=>b=-6a"
"y(2)=8=>8a+4b=8=>b=-2a+2"
"-6a=-2a+2=>a=-\\dfrac{1}{2}"
"b=-6(-\\dfrac{1}{2})=3"
"y=-\\dfrac{1}{2}x^3+3x^2"
"a=-\\dfrac{1}{2}, b=3"
2.
"D(y): (-\\infin, \\infin)"
"E(y): (-\\infin, \\infin)"
"y\\to\\infin" as "x\\to -\\infin"
"y\\to-\\infin" as "x\\to \\infin"
"y(0)=1"
Find the critical number(s)
"x_1=0, x_2=6"
Critical numbers: "0, 6."
"y(6)= \\dfrac{9(6)^2 - (6)^3 + 6}{6}=19"
If "x<0, y'<0, y" decreases.
If "0<x<6, y'>0, y" increases.
If "x>6, y'<0, y" decreases.
The function "y" has the local maximum with value of "19" at "x=6."
The function "y" has the local minimum with value of "1" at "x=0."
"y''=0=>3-x=0=>x=3"
"y(3)= \\dfrac{9(3)^2 - (3)^3 + 6}{6}=10"
If "x<3, y''>0, y" is concave up.
If "x>3, y''<0, y" is concave down.
Point "(3, 10)" is the inflection point.
Graph the function
3.
"D(y): (-\\infin, \\infin)"
"E(y): (-\\infin, \\infin)"
"y\\to-\\infin" as"x\\to -\\infin"
"y\\to\\infin" as"x\\to \\infin"
"y(0)=6"
Find the critical number(s)
"x_1=0, x_2=2"
Critical numbers: "0, 2."
"y(2)=(2)^3 - 3(2)^2 + 6=2"
If "x<0, y'>0, y" increases.
If "0<x<2, y'<0, y" decreases.
If "x>2, y'>0, y" increases.
The function "y" has the local maximum with value of "6" at "x=0."
The function "y" has the local minimum with value of "2" at "x=2."
"y''=0=>6x-6=0=>x=1"
"y(1)=(1)^3 - 3(1)^2 + 6=4"
If "x<1, y''<0, y" is concave down.
If "x>1, y''>0, y" is concave up.
Point "(1, 4)" is the inflection point.
Graph the function
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