Find the volume generated by revolving the area bounded by the lines x + y = 5, x = 0
and y = 0, about x-axis.
V=π∫f2(x)dx=π∫05(5−x)2dx=π(25x−5x2+x3/3)∣05=125π/3V=\pi\int f^2(x)dx=\pi\int_0^5 (5-x)^2dx=\pi(25x-5x^2+x^3/3)|^5_0=125\pi /3V=π∫f2(x)dx=π∫05(5−x)2dx=π(25x−5x2+x3/3)∣05=125π/3
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