1. A graph of parabola has 1 turning point. Let f(x)=ax2+bx+c.
If a function has a maximum value, then a<0.
y-intercept: f(0)=a(0)2+b(0)+c=c
Example;
f(x)=−x2+2x+5
2. As x→−∞,f(x)→−∞
As x→∞,f(x)→∞
If x1,x2 are x-intercepts then
f(x)=a(x−x1)(x−x2)2,a>0
f(0)=−ax1(−x2)2=2 Let a=2,x1=−1,x2=1
f(x)=2(x+1)(x−1)2
3. As x→−∞,f(x)→∞
As x→∞,f(x)→∞
If x1 is x-intercepts then
f(x)=a(x−x1)2,a>0 Let a=1,x=1
f(x)=(x−1)2
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