Answer to Question #257877 in Calculus for prezi

Question #257877

The heat equation in two space dimensions may be expressed in polar coordinates as

𝑢𝑡 = 𝛼 2 [𝑢𝑟𝑟 + 1/𝑟 𝑢𝑟 + 1/𝑟^2 𝑢𝜃𝜃]

Assuming that 𝑢(𝑟, 𝜃,𝑡) = 𝑅(𝑟)𝛩(𝜃)𝑇(𝑡),

find ordinary differential equations satisfied by 𝑅, 𝛩 and 𝑇. 


1
Expert's answer
2021-10-29T01:46:03-0400

From given data;

The heat equation in two space dimensions may be expressed in polar coordinates as

ut=α2[urr+1rur+1r2uθθ]u_t=\alpha^2[u_{rr}+\frac{1}{r}u_r+\frac{1}{r^2}u_{\theta\theta}]

Assuming that ,u(r,θ,t)=R(r)Θ(θ)T(t)u(r,\theta,t)=R(r)\Theta(\theta)T(t)

Now we have to find ordinary differential equations satisfied by R,Θ,TR,\Theta,T

Let us take

u(r,θ,t)=R(r)Θ(θ)T(t)u(r,\theta,t)=R(r)\Theta(\theta)T(t)

ur=R(r)Θ(θ)T(t)u_r=R'(r)\Theta(\theta)T(t)

urr=R(r)Θ(θ)T(t)u_{rr}=R''(r)\Theta(\theta)T(t)

uθ=R(r)Θ(θ)T(t)u_{\theta}=R(r)\Theta'(\theta)T(t)

uθθ=R(r)Θ(θ)T(t)u_{\theta\theta}=R(r)\Theta''(\theta)T(t)

ut=α2[urr+1rur+1r2uθθ]u_t=\alpha^2[u_{rr}+\frac{1}{r}u_r+\frac{1}{r^2}u_{\theta\theta}]

ut=α2[R(r)Θ(θ)T(t)+1rR(r)Θ(θ)T(t)+1r2R(r)Θ(θ)T(t)]u_t=\alpha^2[R''(r)\Theta(\theta)T(t)+\frac{1}{r}R'(r)\Theta(\theta)T(t)+\frac{1}{r^2}R(r)\Theta''(\theta)T(t)]

=R(r)Θ(θ)T(t)=R''(r)\Theta(\theta)T'(t)

ut=R(r)Θ(θ)T(t)u_t=R''(r)\Theta(\theta)T'(t)


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