Question #246048

Suppose that the speed v (in ft/s) of a skydiver t seconds after leaping from a plane is given by the equation š‘£ = 190(1 āˆ’ š‘’ āˆ’ 0.168š‘”).

(a) Graph š‘£ versus š‘”.

(b) By evaluating an appropriate limit, show that the graph of š‘£ versus š‘” has a horizontal asymptote š‘£ = š‘ for an appropriate constant š‘.

(c) What is the physical significance of the constant š‘ in part (b)?


Expert's answer

v(t)=190(1āˆ’eāˆ’0.168t)v(t)=190(1-e^{-0.168t})

(a)








(b)


lim⁔tā†’āˆžv(t)=lim⁔tā†’āˆž(190(1āˆ’eāˆ’0.168t))=190(ft/s)\lim\limits_{t\to\infin}v(t)=\lim\limits_{t\to\infin}(190(1-e^{-0.168t}))=190(ft/s)

The horizontal asymptote is v=190 ft/s.v=190\ ft/s.


(c) It is the terminal velocity of skydiver.



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