Let
Ζ(x) = π₯1/(1βx) .
Make tables of values of Ζ at values of x that approach x = 1 from above and below. Does Ζ(x)
appear to have a limit as x approaches 1? If so, what is it? If not, why not?
Let y=f(x)=x+11βxy=f(x)=\dfrac{x+1}{1-x}y=f(x)=1βxx+1β
Since limβ‘xβ1βf(x)=ΜΈlimβ‘xβ1+f(x),\lim\limits_{x\to1^-}f(x)\not=\lim\limits_{x\to1^+}f(x),xβ1βlimβf(x)ξ =xβ1+limβf(x), then limβ‘xβ1f(x)\lim\limits_{x\to1}f(x)xβ1limβf(x) does not exist.
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