Question #243674

Let ā„’{š‘“(š‘”)} = š¹(š‘ ). Show that š‘“(š‘”) = āˆ’ 1 š‘” ā„’ āˆ’1 {š¹ ′ (š‘ )} Thus, if we know how to invert š¹ ′ (š‘ ) then we know how to invert š¹(š‘ ). Use this information to find the Laplace inverse transform of (i) arctan ( š‘Ž š‘  ), (ii) ln ( š‘ +š‘Ž š‘ āˆ’š‘Ž ). 


Expert's answer

F(s)=∫0āˆžeāˆ’tsf(t)dtF(s)=\int^{\infin}_0e^{-ts}f(t)dt


F′(s)=eāˆ’tsf(t)F'(s)=e^{-ts}f(t)

Lāˆ’1(F(s))=f(t)L^{-1}(F(s))=f(t)

Lāˆ’1(F′(s))=f(t)/(āˆ’t)L^{-1}(F'(s))=f(t)/(-t)

f(t)=āˆ’tLāˆ’1(F′(s))f(t)=-tL^{-1}(F'(s))


i)

F′(s)=a1+s2F'(s)=\frac{a}{1+s^2}

f(t)=āˆ’atsintf(t)=-atsint


ii)

F′(s)=1s+aāˆ’1sāˆ’aF'(s)=\frac{1}{s+a}-\frac{1}{s-a}

f(t)=āˆ’t(eāˆ’atāˆ’eat)f(t)=-t(e^{-at}-e^{at})


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