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Question #233586
find
the limit at infinity of (
2
+x)
30
x (
4
+x)
5
/ (
2
-x)
35
Expert's answer
lim
x
→
∞
(
2
+
x
)
30
×
(
4
+
x
)
5
(
2
−
x
)
35
\lim\limits_{x\to\infin}\dfrac{(2+x)^{30}\times(4+x)^5}{(2-x)^{35}}
x
→
∞
lim
(
2
−
x
)
35
(
2
+
x
)
30
×
(
4
+
x
)
5
=
lim
x
→
∞
(
2
x
+
x
x
)
30
×
(
4
x
+
x
x
)
5
(
2
x
−
x
x
)
35
=\lim\limits_{x\to\infin}\dfrac{(\dfrac{2}{x}+\dfrac{x}{x})^{30}\times(\dfrac{4}{x}+\dfrac{x}{x})^5}{(\dfrac{2}{x}-\dfrac{x}{x})^{35}}
=
x
→
∞
lim
(
x
2
−
x
x
)
35
(
x
2
+
x
x
)
30
×
(
x
4
+
x
x
)
5
=
lim
x
→
∞
(
2
x
+
1
)
30
×
(
4
x
+
1
)
5
(
2
x
−
1
)
35
=\lim\limits_{x\to\infin}\dfrac{(\dfrac{2}{x}+1)^{30}\times(\dfrac{4}{x}+1)^5}{(\dfrac{2}{x}-1)^{35}}
=
x
→
∞
lim
(
x
2
−
1
)
35
(
x
2
+
1
)
30
×
(
x
4
+
1
)
5
=
(
0
+
1
)
30
×
(
0
+
1
)
5
(
0
−
1
)
35
=\dfrac{(0+1)^{30}\times(0+1)^5}{(0-1)^{35}}
=
(
0
−
1
)
35
(
0
+
1
)
30
×
(
0
+
1
)
5
=
−
1
=-1
=
−
1
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on Dec 2023
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