evaluate
We have
In = "\\int cosec^n x \\ dx"
In = "\\int" cosecn-2 x cosec2 x dx
Now integrating the above expression by by using the formula of "\\int" uv dx.
Considering cosecn-2 x = u and cosec2 x = v. We have,
In = cosecn-2 x "\\int" cosec2 x dx - "\\int" [ "\\dfrac{d}{dx}" (cosecn-2 x) "\\int" cosec2 x dx ] dx
In = - cosecn-2 x cot x - "\\int" [ (n-2) cosecn-3 x cosec x cot2 x] dx
In = - cosecn-2 x cot x - "\\int" [ (n-2) cosecn-2 x (cosec2 x - 1) ] dx
In = - cosecn-2 x cot x - (n - 2) "\\int" [ cosecn x - cosecn-2 x ] dx ...............equation(1)
Noe from the above equation it can be seen that
In = "\\int" cosecn x dx and In-2 = "\\int" cosecn-2 x dx .................equation(2)
So on substituting the values from equation(2) to equation(1), we have
In = - cosecn-2 x cot x - (n - 2) [ In - In-2 ]
In (n - 1) = - cosecn-2 x cot x + (n - 2) In-2
In = "\\dfrac{-1}{n-1}" cosecn-2 x cot x + "\\dfrac{n-2}{n-1}" In-2
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