lim(x,y)→(0,0)x3y3x3+y3puty=mxlimx→0x31+m3=0Thus, limit exists and is equal to 0.lim_{(x,y)\to (0,0)} \frac{x^3y^3}{x^3+y^3}\\ \text{put}y=mx\\ lim_{x\to 0} \frac{x^3}{1+m^3}\\ =0\\ \text{Thus, limit exists and is equal to 0.}lim(x,y)→(0,0)x3+y3x3y3puty=mxlimx→01+m3x3=0Thus, limit exists and is equal to 0.
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