Answer to Question #217631 in Calculus for nick

Question #217631

Prove that

∑_(i=5)^20▒〖3.2^i 〗= ∑_(k=0)^15▒〖96.2^k 〗

Expert's answer

Use calculator

\displaystyle\sum_{i=5}^{20}(3.2)^i\approx18438554032.6177

\displaystyle\sum_{k=0}^{15}(96.2)^k\approx5.65150614585858⋅10^{29}

Therefore the statement is false.

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