Question #217916
Evulate ∫ (2x^2 + 3y^2)sc, where C is the curve
C
x(t)= at^2, y(t) = 2at, 0≤t≤1
1
Expert's answer
2021-07-19T05:51:53-0400

(2x2dx+3y2dy)x(t)=at2    dx=2atdty(t)=2at    dy=2adt(2x2dx+3y2dy)=012(at2)22atdt+3(2at)22adt014a3t5dt+0112a3t2dt014a3t5dt+0112a3t2dt23a3+4a314a33∫ (2x^2 dx+ 3y^2dy)\\ x(t)= at^2 \implies dx=2atdt\\ y(t) = 2at\implies dy =2adt\\ ∫ (2x^2 dx+ 3y^2dy)=∫_0^12(at^2)^2*2atdt+3(2at)^22adt\\ ∫_0^14a^3t^5dt+∫_0^112a^3t^2dt\\ ∫_0^14a^3t^5dt+∫_0^112a^3t^2dt\\ \frac{2}{3}a^3+4a^3\\ \frac{14a^3}{3}



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