f(x)=3x4−4x3−12x2+8
differentiating with respect to x
f′(x)=12x3−12x2−24x
to find stationary points put f′(x)=0
⇒12x3−12x2−24x=0
⇒x3−x2−2x=0
⇒x(x2−x−2)=0
⇒x(x−2)(x+1)=0
stationary points are
x=−1,0,2
differentiating again with respect to x
f′′(x)=36x2−24x−24
f′′(−1)=36>0 (x=−1 is local minimum)
f′′(0)=−24<0 (x=0 is local maximum)
f′′(2)=72>0 (x=2 is local minimum)
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