Question #203424

Find ∫ 𝑥𝑐𝑜𝑠 𝑥𝑑x


1
Expert's answer
2021-06-15T05:01:00-0400

Solution.


xcosxdx\int x \cos xdx


To calculate this integral we use the method of integration by parts.

Let be u=x,dv=cosxdx.u=x, dv=\cos {x} dx.

From here du=1,v=sinx.du=1, v=\sin x.

Therefore, xcosxdx=xsinx1sinxdx=xsinx+cosx+C,\int x\cos xdx=x\sin x-\int 1\cdot\sin xdx=x\sin x+\cos x+C,

where CC is some constant.

Answer.


xcosxdx=xsinx+cosx+C.\int x\cos xdx=x\sin x+\cos x+C.


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