Answer to Question #202354 in Calculus for someone

Question #202354

Use a graphing calculator, or another piece of technology, to find the zeros of the function f(x)=−2x^3+5x^2+1

What are the approximate zeros to the nearest tenth?

There may be more than one correct answer. Select all correct answers.


  • x≈0.2
  • x≈−0.2
  • x≈1.7
  • x≈−2.58
  • x≈−1.7
  • x≈2.58
1
Expert's answer
2021-06-11T16:35:39-0400

Solution:

Graph of "f(x)=\u22122x^3+5x^2+1" is:



Clearly, it intersects x-axis at only one point, so it has one real root, i.e. "x=2.575"

So, we get "x\\approx 2.58" only (option 6).


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