Use a graphing calculator, or another piece of technology, to find the zeros of the function f(x)=−2x^3+5x^2+1
What are the approximate zeros to the nearest tenth?
There may be more than one correct answer. Select all correct answers.
Solution:
Graph of "f(x)=\u22122x^3+5x^2+1" is:
Clearly, it intersects x-axis at only one point, so it has one real root, i.e. "x=2.575"
So, we get "x\\approx 2.58" only (option 6).
Comments
Leave a comment