Answer to Question #201864 in Calculus for Femi

Question

Lim_x→1⁺ (³√x+1) In(x+1)

Answer 1

$$\lim\limits_{x\to 1^+}(\sqrt[3]{x}+1)\ln(x+1)$$

$$=\lim\limits_{x\to 1^+}(\sqrt[3]{x}+1)\cdot\lim\limits_{x\to 1^+}\ln(x+1)$$

$$=(\sqrt[3]{1}+1)\cdot\ln(1+1)=2\ln2$$