Verify Euler's realtion for
z= tan(y/x) ,x ≠ 0
We have given that,
z=f(x,y)=tanyxz = f(x,y) = tan\dfrac{y}{x}z=f(x,y)=tanxy x≠0x \ne 0x=0
We have to prove that,
xδfδx+yδfδy=−fx \dfrac{\delta f}{\delta x} + y \dfrac{\delta f}{\delta y} = -fxδxδf+yδyδf=−f
Solving the LHS
xδfδx+yδfδy=−yxsec2yx+yxsec2yx=0x \dfrac{\delta f}{\delta x} + y \dfrac{\delta f}{\delta y} = -\dfrac{y}{x}sec^2\dfrac{y}{x}+\dfrac{y}{x}sec^2\dfrac{y}{x} = 0xδxδf+yδyδf=−xysec2xy+xysec2xy=0
which is not equal to RHS. Hence, Euler's relation is not valid.
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