Question #190414

Verify Euler's realtion for

z= tan(y/x) ,x ≠ 0


1
Expert's answer
2021-05-07T14:31:49-0400

We have given that,

z=f(x,y)=tanyxz = f(x,y) = tan\dfrac{y}{x} x0x \ne 0


We have to prove that,

xδfδx+yδfδy=fx \dfrac{\delta f}{\delta x} + y \dfrac{\delta f}{\delta y} = -f


Solving the LHS


xδfδx+yδfδy=yxsec2yx+yxsec2yx=0x \dfrac{\delta f}{\delta x} + y \dfrac{\delta f}{\delta y} = -\dfrac{y}{x}sec^2\dfrac{y}{x}+\dfrac{y}{x}sec^2\dfrac{y}{x} = 0


which is not equal to RHS. Hence, Euler's relation is not valid.


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