Question #190411

Let the function,f be defined by

f(x,y) = { 3x^2y^4/(x^4+y^4) , (x,y)≠(0,0)

{ 0 ,(x,y)={0,0)

Show that f has directional derivatives in all directions at (0,0).


Expert's answer

We have given the function,

f(x,y)=3x2y4x4+y4f(x,y) = \dfrac{3x^2y^4}{x^4+y^4} , if (x,y)(0,0)(x,y) \ne (0,0)

= 0 , if(x,y)=(0,0)if (x,y) = (0,0)


Direct computation yields for every v=(x,y)R2v = (x,y) \in R^2


Dv(f)=limt0f(0+tv)f(0)tD_v(f) = limt \rightarrow 0 \dfrac{f(0+tv)-f(0)}{t}


=0= 0

Thus f(x,y)f(x,y)  has directional derivatives in all directions at (0,0)(0,0).



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