Question #188348

X3-2x is it odd function or even


Expert's answer

Let f(x)=x32xf(x)=x^3-2x

Require to verify whether the given function f(x)f(x) is even or odd.


Recollect the following:

A function f(x)f(x) is said to be even function if f(x)=f(x)f(-x)=f(x) and

A function f(x)f(x) is said to be odd function if f(x)=f(x)f(-x)=-f(x)


Now f(x)=x32xf(x)=(x)32(x)f(x)=x^3-2x\Rightarrow f(-x)=(-x)^3-2(-x)

f(x)=x3+2x\Rightarrow f(-x)=-x^3+2x

f(x)=(x32x)\Rightarrow f(-x)=-(x^3-2x)

f(x)=f(x)\Rightarrow f(-x)=-f(x)

Therefore, the given function is odd function.


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