Differentiate the following functions:
y = (t^3 - 5)^1/a
Given function is-
y=(t3−5)1ay=(t^3-5)^{\frac{1}{a}}y=(t3−5)a1
Differentiate with respect to x−x-x−
dydt=1a(t3−5)1a−1×3t2y′(t)=3t2a(t3−5)1−aa\dfrac{dy}{dt}=\dfrac{1}{a}(t^3-5)^{\frac{1}{a}-1}\times 3t^2\\[9pt]y'(t)=\dfrac{3t^2}{a}(t^3-5)^{\frac{1-a}{a}}dtdy=a1(t3−5)a1−1×3t2y′(t)=a3t2(t3−5)a1−a
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