Answer in Calculus for VPM #188147

Question #188147

5. A projectile is fired vertically upwards with height h given by: h = 25t - 4.9^2 where 0 ≤ t ≤ 5

Expert's answer

if we need find: $h(5)=25*5-4.9*5*5=25(5-4.9)=2.5$

if we need find $h_{max},h'(t)=25-2*4.9*t$ decreases, $h'(t_*)=0$ ,

$t_*=\frac{25}{2*4.9}$ , $\implies h_{max}=h(t_*)=25*\frac{25}{2*4.9}-4.9*\frac{25}{2*4.9}*\frac{25}{2*4.9}=$

$=\frac{625}{2*4.9}(1-\frac{1}{2})=\frac{625}{4*4.9}$

if we need find $t_{1,2}|h(t_{1,2})=0,h(t)=t*(25-4.9t)=0\implies t_1=0,t_2=\frac{25}{4.9}$

Learn more about our help with Assignments: Calculus Pre-Calculus Differential Calculus Multivariable Calculus

Comments

Assignment Expert

10.05.21, 12:23

Dear VPM, please use the panel for submitting a new question. Please describe all math formulae, conditions of the question completely and correctly so that our experts could solve a new question according to new requirements.

VPM

08.05.21, 13:07

I missed out on some of the questions as the teacher recently added to the question: 5. A projectile is fired vertically upwards with height h given by: h = 25t - 4.9^2 where 0 ≤ t ≤ 5 Find expressions for the velocity and acceleration. Determine the maximum height reached by the projectile