Differentiate the following functions:
(a) y = `4√x + 4/x + 3 ln x
Let us differentiate the function
y=4x+4x+3lnx:y = 4\sqrt{x} +\frac{ 4}{x} + 3 \ln x:y=4x+x4+3lnx:
y′=412x−4x2+3x=2x−4x2+3xy '= 4\frac{1}{2\sqrt{x}} -\frac{ 4}{x^2} + \frac{3 }{ x}= \frac{2}{\sqrt{x}} -\frac{ 4}{x^2} + \frac{3 }{ x}y′=42x1−x24+x3=x2−x24+x3
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