In June 2024
Answer to Question #186232 in Calculus for Innocent Lorita
Let f(x)=3x-3,g(x)=x+1,h(x)=3x+12. Then (fogohogohogohogoh)(0)=
"h(x)=3x+12\\newline\ng(h(x))=g(3x+12)=3x+13\\newline\nh(g(h(x)))=h(3x+13)=9x+51\\newline\ng(h(g(h(x))))=g(9x+51)=9x+52\\newline\nh(g(h(g(h(x)))))=h(9x+52)=27x+168\\newline\ng(h(g(h(g(h(x))))))=g(27x+168)=27x+169\\newline\nh(g(h(g(h(g(h(x)))))))=h(27x+169)=81x+519\\newline\ng(h(g(h(g(h(g(h(x))))))))=g(81x+519)=81x+520\\newline\nf(g(h(g(h(g(h(g(h(x)))))))))=f(81x+520)=243x+1557\\newline\n\\text{put x=0},\\newline\nf(g(h(g(h(g(h(g(h(0)))))))))=1557"
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#339914 on Dec 2023
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