Question #180316

Find the area bounded by y = 2; y = √x + 2; and y = 2 - x

1
Expert's answer
2021-05-10T18:22:41-0400

Let

y=2(i)y=x+2(ii)y=2x(iii)y = 2 \qquad \cdots (i)\\ y = \sqrt{x} + 2 \qquad \cdots (ii)\\ y = 2 - x \qquad \cdots (iii)


We proceed to check the boundary points of the curve.

From (i) and (ii)


2=x+2x=22x=0x=02=\sqrt x+2\\ \sqrt x = 2-2\\ \sqrt x =0\\ x=0

From (i) and (iii)

2=2xx=22x=02=2-x\\ x=2-2\\ x=0

From (ii) and (iii)


x+2=2x    x=0\sqrt x + 2 = 2-x\\ \implies x=0

Since the value of x is zero for all the three functions, then, the curves not bounded and therefore, NO SOLUTION


A graph of this is shown below:


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