Find f' in terms of g' of f(x)=g(x)(x-a)
Solution:
Given, "f(x)=g(x)(x-a)"
On differentiating both sides w.r.t "x" ,
"f'(x)=[g(x)]'(x-a)+g(x)(x-a)'" [Using product rule]
"\\Rightarrow f'(x)=g'(x)(x-a)+g(x)(1-0)"
"\\Rightarrow f'(x)=g'(x)(x-a)+g(x)"
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