Answer to Question #167810 in Calculus for Phyroe

Question #167810

Evaluate the integral of Csc² (2-3x) dx


1
Expert's answer
2021-03-09T02:13:00-0500

Solution:

I=csc2(23x)dxI=\int \csc^2 (2-3x)dx ...(i)

Put 23x=t2-3x=t

03=dtdx\Rightarrow 0-3=\dfrac{dt}{dx} [On differentiating]

dx=dt3\Rightarrow dx=-\dfrac{dt}{3}

Putting these values in (i), we get

I=13(csc2t)dt\Rightarrow I=\dfrac13\int(- \csc^2 t)dt

I=13cott+C\Rightarrow I=\dfrac13\cot t+C

I=13cot(23x)+C\Rightarrow I=\dfrac13\cot (2-3x)+C [Substituting value of tt back]



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